On Sunday 30 November 2003 19:50, Skip Montanaro wrote: > How about you allow both keyword args and an explicit attribute dict? That > way, for the oddball stuff which clashes with Python syntax you go the > extra step and use the dictionary, but for normal usage, keyword args do > just fine: > > htmltag('input', type='text', size=20, maxlength=40) > htmltag('textarea', rows=30, cols=80) > htmltag('body', bgcolor='#fff', attrs={'class': 'mainpage'}) > I miss something or may be i haven't understood nothing. Have you tested all this stuff with the last html.py patch proposed? I think all of these examples are already supported. > Most of the time you won't need the attrs argument, but when you do > encounter a recalcitrant attribute name, you won't have to remember how to > sneak it by the Python parser. Of course, purists are free to just use > attrs: > > htmltag('input', attrs={'type': 'text', 'size': 20, 'maxlength': 40}) > htmltag('textarea', attrs={'rows': 30, 'cols': 80}) > htmltag('body', attrs={'bgcolor': '#fff', 'class': 'mainpage'}) > Maybe you are talking about widget instead of htmltag. Then, as a old algebra teacher liked to say: Aren't you merging potatoes with tomatoes? Greg Ward said: >OK, the "Generalizing frame/widget framework a bit" thread had lots of >good things to say. I'm attaching a patch in two parts that, IMHO, >represents the group consensus. This is relative to Quixote 0.7a2; my >previous patch in this direction is withdrawn. I'm really happy with the resolution of this thread is taking. I'm going to test it. Thank you for your comprehension. Greg> because those constructor keyword args are just darn convenient. I think this is a widget constructor decission. In this case, yours. htmltag doc says: Note that keyword args are transformed into tag attributes in hash order (ie. unpredictable and subject to change across Python versions). I have already thought on this. Several unclear solutions appear to me: A sort function inside htmlattrs (awkful?), subclassing dict for htmlattrs(expensive?). As a secondary matter, i wouldn't like to begin a subthread on this now. Oscar Rambla CODI