I'm sorry but the correct balance of reaction (and the forming species) is
the following:

H2O2 + H2SO4 = HSO4(-) + H3O(+) + OH

......this is a redox reaction in wich the oxygen change its oxidation
state.....

see for more details on the reaction mechanism the following paper...

http://www.springerlink.com/content/t582t7267w88k835/fulltext.pdf

Bye
Edmondo

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From: "DEBASHIS MAJI" 
Sent: Tuesday, January 26, 2010 9:23 PM
To: "General MEMS discussion" 
Subject: [mems-talk] Piranha Reaction

> Dear all,
>
> I shall be highly thankful if anyone can kindly tell the effect of change
> in
> the ratio of H2O2 and H2SO4 (normally 1:1) in Piranha solution. I know
> that
> this reaction takes place in the following order : H2O2 + H2SO4 = HSO4(-)
> +
> H3O(+) + O. It is this nascent oxygen that is used in cleaning or surface
> treatment, etc. I would like to know the effect of increase in sulphuric
> acid conc. say from 1:1 to 3:1 in the piranha solution. Would it result in
> more vigorous reaction with more nascent O? if so how do the equations
> go...?
>
> Kindly help me out regarding this. Thanks in advance.
>
> Debashis Maji